The second law of dynamics
We have combined with a mass of 1 kg of a spring and we have a spurt of 2 m / s ^ 2. To measure the acceleration of the body we used a motion sensor connected via a USB interface Pasporta-supplied PC program DataStudio.
We have carefully measured the elongation Δl of the spring associated with the force that the spring exerts on the block. We then replaced with another body of mass m 1 and applied to that body the same force, that which produces the same stretch of the spring measured in the previous case (we have assumed that the force of the spring is proportional to elongation thereof). In this case we measured an acceleration other than 2 m / s ^ 2, ie 0.5 m / s ^ 2. Is defined as the ratio of mass of the two bodies of the mutual relationship of the two acceleration impressed on them by the same force: 1 m / m = a 0 0 / a 1.
The second body, which undergoes an acceleration equal to one fourth that of the first body with the same force acting, has a mass four times greater.
Finally, we verified that the relationship between the two masses is independent of the applied force, if this is the same for both: so we repeated the experience with a force that acts different, and we found: m 1 / m = a 0 0 / a 1 = a 0 '/ a 1'.
We have combined with a mass of 1 kg of a spring and we have a spurt of 2 m / s ^ 2. To measure the acceleration of the body we used a motion sensor connected via a USB interface Pasporta-supplied PC program DataStudio.
We have carefully measured the elongation Δl of the spring associated with the force that the spring exerts on the block. We then replaced with another body of mass m 1 and applied to that body the same force, that which produces the same stretch of the spring measured in the previous case (we have assumed that the force of the spring is proportional to elongation thereof). In this case we measured an acceleration other than 2 m / s ^ 2, ie 0.5 m / s ^ 2. Is defined as the ratio of mass of the two bodies of the mutual relationship of the two acceleration impressed on them by the same force: 1 m / m = a 0 0 / a 1.
The second body, which undergoes an acceleration equal to one fourth that of the first body with the same force acting, has a mass four times greater.
Finally, we verified that the relationship between the two masses is independent of the applied force, if this is the same for both: so we repeated the experience with a force that acts different, and we found: m 1 / m = a 0 0 / a 1 = a 0 '/ a 1'.
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